72h-3h^2=0

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Solution for 72h-3h^2=0 equation:



72h-3h^2=0
a = -3; b = 72; c = 0;
Δ = b2-4ac
Δ = 722-4·(-3)·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-72}{2*-3}=\frac{-144}{-6} =+24 $
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+72}{2*-3}=\frac{0}{-6} =0 $

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